mail() help again, can not receive the email sent.

General Web Coding PHP and MySQL
1

Hi,
I started to learn php yesterday.
And wrote my first php file.
It calls the mail() to send an email.

code:

…
ini_set(SMTP,“localhost”);
ini_set(smtp_port,8081);
mail( “[email protected]”, “Feedback Form Results”,
$message, “From: $email” );
header( “Location: http://www.google.com” );
…

After I testing the php, it showed me the email was sent successfully( without any error information and opened the www.google.com) . But I can not find the email sent in the [email protected].
I have downloaded a software called Free SMTP Server to run on my machine. It also showed me my php program used the port 8081 to send the email.

appreciate any help…

2

Port 8081 is an odd one for SMTP. You might want to confirm that. Typical is 25. You could change your code to:

[PHP]$returnValue = mail( “[email protected]”, “Feedback Form Results”, $message, “From: $email” );
if($returnValue === true) echo ‘Success!’;
else echo ‘Sending failed’;
[/PHP]

That will tell you if mail() talked to your SMTP server or not. If it is, perhaps your mail is being sent but blocked by a spam filter? You’re not using complete headers, which is sometimes seen as a sign that a message is spam. Here’s a snippet of code from a mail script I’ve written:

[PHP]$headers = “MIME-Version: 1.0\r\n”;
$headers .= “Content-type: text/plain; charset=iso-8859-1\r\n”;
$headers .= “X-Priority: 1\r\n”;
$headers .= “X-MSMail-Priority: High\r\n”;
$headers .= “X-Mailer: php\r\n”;
$headers .= "From: " . $from . “\r\n”;
$headers .= "Reply-To: " . $from . “\r\n”;
if(strlen(trim($cc)) > 0) {
$headers .= "CC: " . $cc . “\r\n”;
}
if(strlen(trim($bcc)) > 0) {
$headers .= "BCC: " . $bcc . “\r\n”;
}
mail($to, $subject, $body, $headers);
[/PHP]

(Check out http://www.skypanther.com/spmailer.php for the full code.)

Tim